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How do you find delta h1 and delta h3

can you make for h2o2 beacoming h2o and o2?

what is the question fpr this problem? i mean in words of paragraph?

What's the reason for changing curve concavity by changing fluid? Does it depend on varying K or Cp values by temperature along the heat exchanger?

I DO NOT agree that there is no work in this problem, the volume is increasing 4 fold for christ sakes!! Plus, the piston is being moved for crying out loud!! Total Bull on this one Falconer!!!

Awesome! a very clear explination.

I guess this formula is for UA clean & in case of UA dirty we have to add the fouling factor contributions on the inner & outer of the surface as well. What is the equation for that? Will the fouling factors be assumed from literature or calculated?

Indeed a picture is worth thousand words.

Thanks for the explanation in detail. In case of the reboiler using heat transfer fluid other steam which does not change phase i.e. hot oil, will the heat transfer coefficient of the reboiler be the same as that of the condenser?

Using userform with checkbox in WORD?

Could you explain why in the eq 7 there is + in front of the x1*W, when I found its originally - there

1:02 I have been unable to put/spin the turbun onto my head using this system, any ideas?

So helpful, thanks

Why is there a coefficient of "2" in the mass balance for A? I thought that was already accounted for with the Ca^2

May I know which simulator are you using?

What is x? And what is the purpose of solving x=0.91?

You multiply the H values (BTU per lb) by the total pounds of each stream in your energy balance. Are the units of H in "BTU per lb of total mixture" or "BTU per lb of H2SO4"? If you think about it, the enthalpy of mixing arises from mixing the H2SO4, not the other stuff in solution (which should be arbitrary to the total heat). So accounting for only the masses of H2SO4 from in and out of the mixer in the energy balance makes most sense to me. Is this logic flawed?

We are taking the differential element, then why rdθ why not ∆rdθ?

Great Video. Just to mention, your link doesnt work for the calculator.

Also, keep in mind that this video uses the Darcy friction factor (64/Re = f for laminar flow) as opposed to the Fanning friction factor (16/Re = f for laminar flow). Therefore, (7:32) h_L = f(L/D)*v^2/(2*g) is correct for Darcy friction factors, but h_L = 2f(L/D)*v^2/g for fanning friction factors. The friction factors are essentially different by a factor of 4 (therefore f_f * 4 = f_d).

(4:46) The exact numbers are debated, but generally Re<2100 is laminar, 2100<Re<4000 is transitional, and 4000<Re is turbulent. In engineering practice, 10,000 < Re is fully turbulent (this is for internal flow through pipe).

For anyone who was wondering, I think the friction factor used in this video is the Darcy friction factor (64/Re = f) as opposed to the typical Fanning friction factor used by Chemical Engineers (16/Re = f). Both are equally valid, but it should always be specified which is being used. To get from Fanning to Darcy friction factors multiply the fanning friction factor by 4 (f_F * 4 = f_D)

thank you this video is really amazing

Good video mate

12yr later u r a life saver m gonna younk this derivation nd write it in my Master degree exam Ps-studying this 3 hr befor exam u r life saver 😢

I love this guy

thank you so much. I read many and many explaination but I cannot understand until saw yours

Thanks

Great illustration

Excellent video thx

Thanks

Thank you

C is the correct answer

You are a wonderful teacher. Please make videos on thermodynamics. You explain all little steps . Thank you very much .

Well, i did the calculations and got -39.1Kj for one mole total of condensing the mentioned gas mixture of CH3OH and H2O.

You need to put a compressor/limiter on your vocals

How are you getting Z value???

I have never understood the actual meaning of DOF.

Thank you for helping the automation industry, we all have to do our part to help the growth

See the running carnot engine. ruclips.net/video/CpsgxnJgepE/видео.html&pp=ygUUUm90YXJ5IENhcm5vdCBFbmdpbmU%3D

2:49 where is the notation for partial derivative w.r.t. Y

Good stuff

How pressure remains constant in condenser despite the temperature drop from superheat rejection after compressor & sub-cooling heat rejection before expansion valve? Thank u How pressure remains constant in evaporator despite temperature rise from superheat gain before compressor?

Hi ,@3:54, T is indepent of density, which I don't understand , could you explain??

el yazını sikeyim

I have some questions I want discussion with who have experenice with membrane , if have email ,u can tell me it i will message u

This was very helpful, thanks to you❤️🙏🏾

there is a trick in Question 4 for me. So in this case, the kinematic viscosity of air > water, so the critical point of air is further (according to the formula). But in reality, the fluid with smaller kinematic viscosity, its critical point will be further! This means water will have the further point! Can you help me to explain, thank you so much!

How to graph it using equilateral? Its so confusing…